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The Dawn of Space and Time in a Selfconscious Quantum Universe

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Next: Potential formulation Up: Time-dependent Maxwell's equations Previous: Gauge transformations

The displacement current

Michael Faraday revolutionized physics in 1830 by showing that electricity and magnetism were interrelated phenomena. He achieved this breakthrough by careful experimentation. Between 1864 and 1873, James Clerk Maxwell achieved a similar breakthrough by pure thought. Of course, this was only possible because he was able to take the experimental results of Faraday, Ampère, etc., as his starting point. Prior to 1864, the laws of electromagnetism were written in integral form. Thus, Gauss's law was (in S.I. units) the flux of the electric field through a closed surface equals the total enclosed charge, divided by $\epsilon_0$ . The no magnetic monopole law was the flux of the magnetic field through any closed surface is zero. Faraday's law was the electromotive force generated around a closed loop equals minus the rate of change of the magnetic flux through the loop. Finally, Ampère's circuital law was the line integral of the magnetic field around a closed loop equals the total current flowing through the loop, multiplied by $\mu_0$ . Maxwell's first great achievement was to realize that these laws could be expressed as a set of first-order partial differential equations. Of course, he wrote his equations out in component form, because modern vector notation did not come into vogue until about the time of the First World War. In modern notation, Maxwell first wrote:

$\displaystyle \nabla\cdot{\bf E}$ $\textstyle =$ $\displaystyle \frac{\rho}{\epsilon_0},$ (400)

$\displaystyle \nabla\cdot{\bf B}$ $\textstyle =$ $\displaystyle 0,$ (401)

$\displaystyle \nabla\times{\bf E}$ $\textstyle =$ $\displaystyle - \frac{\partial {\bf B}}{\partial t} ,$ (402)

$\displaystyle \nabla\times{\bf B}$ $\textstyle =$ $\displaystyle \mu_0 {\bf j}.$ (403)

Maxwell's second great achievement was to realize that these equations are wrong.
We can see that there is something slightly unusual about Eqs. (400)-(403). They are very unfair to electric fields! After all, time-varying magnetic fields can induce electric fields, but electric fields apparently cannot affect magnetic fields in any way. However, there is a far more serious problem associated with the above equations, which we alluded to earlier on. Consider the integral form of the last Maxwell equation (i.e., Ampère's circuital law)

$\begin{displaymath}
\oint_C {\bf B} \cdot d{\bf l} = \mu_0 \int_S {\bf j} \cdot d{\bf S}.
\end{displaymath}$

The displacement current
Michael Faraday revolutionized physics in 1830 by showing that electricity and magnetism were interrelated phenomena. He achieved this breakthrough by careful experimentation. Between 1864 and 1873, James Clerk Maxwell achieved a similar breakthrough by pure thought. Of course, this was only possible because he was able to take the experimental results of Faraday, Ampère, etc., as his starting point. Prior to 1864, the laws of electromagnetism were written in integral form. Thus, Gauss's law was (in S.I. units) the flux of the electric field through a closed surface equals the total enclosed charge, divided by $\epsilon_0$ . The no magnetic monopole law was the flux of the magnetic field through any closed surface is zero. Faraday's law was the electromotive force generated around a closed loop equals minus the rate of change of the magnetic flux through the loop. Finally, Ampère's circuital law was the line integral of the magnetic field around a closed loop equals the total current flowing through the loop, multiplied by $\mu_0$ . Maxwell's first great achievement was to realize that these laws could be expressed as a set of first-order partial differential equations. Of course, he wrote his equations out in component form, because modern vector notation did not come into vogue until about the time of the First World War. In modern notation, Maxwell first wrote:

$\displaystyle \nabla\cdot{\bf E}$ $\textstyle =$ $\displaystyle \frac{\rho}{\epsilon_0},$ (400)

$\displaystyle \nabla\cdot{\bf B}$ $\textstyle =$ $\displaystyle 0,$ (401)

$\displaystyle \nabla\times{\bf E}$ $\textstyle =$ $\displaystyle - \frac{\partial {\bf B}}{\partial t} ,$ (402)

$\displaystyle \nabla\times{\bf B}$ $\textstyle =$ $\displaystyle \mu_0 {\bf j}.$ (403)

Maxwell's second great achievement was to realize that these equations are wrong.
We can see that there is something slightly unusual about Eqs. (400)-(403). They are very unfair to electric fields! After all, time-varying magnetic fields can induce electric fields, but electric fields apparently cannot affect magnetic fields in any way. However, there is a far more serious problem associated with the above equations, which we alluded to earlier on. Consider the integral form of the last Maxwell equation (i.e., Ampère's circuital law)

$\begin{displaymath}
\oint_C {\bf B} \cdot d{\bf l} = \mu_0 \int_S {\bf j} \cdot d{\bf S}.
\end{displaymath}$ (404)

This says that the line integral of the magnetic field around a closed loop is equal to $\mu_0$ times the flux of the current density through the loop. The problem is that the flux of the current density through a loop is not, in general, a well-defined quantity. In order for the flux to be well-defined, the integral of ${\bf j}\cdot d{\bf S}$ over some surface attached to a loop must depend on , but not on the details of . This is only the case if

$\begin{displaymath}
\nabla\cdot{\bf j} = 0.
\end{displaymath}$ (405)

Unfortunately, the above condition is only satisfied for non time-varying fields.
Why do we say that, in general, $\nabla\cdot{\bf j} \neq 0$ ? Well, consider the flux of ${\bf j}$ out of some closed surface enclosing a volume . This is clearly equivalent to the rate at which charge flows out of . However, if charge is a conserved quantity (and we certainly believe that it is) then the rate at which charge flows out of must equal the rate of decrease of the charge contained in volume . Thus,

$\begin{displaymath}
\oint_S {\bf j} \cdot d{\bf S} = - \frac{\partial}{\partial t}\!
\int_V \rho dV.
\end{displaymath}$ (406)

Making use of Gauss' theorem, this yields

$\begin{displaymath}
\nabla\cdot{\bf j} = -\frac{\partial \rho}{\partial t}.
\end{displaymath}$ (407)

Thus, $\nabla\cdot{\bf j} = 0$ is only true in a steady-state (i.e., when $\partial/\partial t \equiv 0$ ).
The problem with Ampère's circuital law is well illustrated by the following very famous example. Consider a long straight wire interrupted by a parallel plate capacitor. Suppose that is some loop which circles the wire. In the non time-dependent situation, the capacitor acts like a break in the wire, so no current flows, and no magnetic field is generated. There is clearly no problem with Ampère's law in this case. However, in the time-dependent situation, a transient current flows in the wire as the capacitor charges up, or charges down, and so a transient magnetic field is generated. Thus, the line integral of the magnetic field around is (transiently) non-zero. According to Ampère's circuital law, the flux of the current through any surface attached to should also be (transiently) non-zero. Let us consider two such surfaces. The first surface, , intersects the wire. This surface causes us no problem, since the flux of ${\bf j}$ though the surface is clearly non-zero (because it intersects a current carrying wire). The second surface, , passes between the plates of the capacitor, and, therefore, does not intersect the wire at all. Clearly, the flux of the current through this surface is zero. The current fluxes through surfaces and are obviously different. However, both surfaces are attached to the same loop , so the fluxes should be the same, according to Ampère's law (404). It would appear that Ampère's circuital law is about to disintegrate! However, we notice that although the surface does not intersect any electric current, it does pass through a region of strong changing electric field as it threads between the plates of the charging (or discharging) capacitor. Perhaps, if we add a term involving $\partial {\bf E}/{\partial t}$ to the right-hand side of Eq. (403) then we can somehow fix up Ampère's circuital law? This is, essentially, how Maxwell reasoned more than one hundred years ago.
Let us try out this scheme. Suppose that we write

$\begin{displaymath}
\nabla\times{\bf B} = \mu_0 {\bf j} +\lambda \frac{\partial {\bf E}}{\partial t}
\end{displaymath}$ (408)

instead of Eq. (403). Here, $\lambda$ is some constant. Does this resolve our problem? We want the flux of the right-hand side of the above equation through some loop to be well-defined; i.e., it should only depend on , and not the particular surface (which spans ) upon which it is evaluated. This is another way of saying that we want the divergence of the right-hand side to be zero. In fact, we can see that this is necessary for self-consistency, since the divergence of the left-hand side is automatically zero. So, taking the divergence of Eq. (408), we obtain

$\begin{displaymath}
0= \mu_0 \nabla\cdot{\bf j} +\lambda \frac{\partial 
\nabla\cdot{\bf E}}{\partial t}.
\end{displaymath}$ (409)

But, we know that

$\begin{displaymath}
\nabla\cdot{\bf E} = \frac{\rho}{\epsilon_0},
\end{displaymath}$ (410)

so combining the previous two equations we arrive at

$\begin{displaymath}
\mu_0 \nabla\cdot{\bf j} + \frac{\lambda}{\epsilon_0} \frac{\partial\rho}{\partial t}
=0.
\end{displaymath}$ (411)

Now, our charge conservation law (407) can be written

$\begin{displaymath}
\nabla\cdot{\bf j} +\frac{\partial\rho}{\partial t} = 0.
\end{displaymath}$ (412)

The previous two equations are in agreement provided $\lambda = \epsilon_0\mu_0$ . So, if we modify the final Maxwell equation such that it reads

$\begin{displaymath}
\nabla\times{\bf B} = \mu_0 {\bf j} + \epsilon_0\mu_0 \frac{\partial {\bf E}}{\partial
t},
\end{displaymath}$ (413)

then we find that the divergence of the right-hand side is zero as a consequence of charge conservation. The extra term is called the displacement current (this name was invented by Maxwell). In summary, we have shown that although the flux of the real current through a loop is not well-defined, if we form the sum of the real current and the displacement current then the flux of this new quantity through a loop is well-defined.
Of course, the displacement current is not a current at all. It is, in fact, associated with the generation of magnetic fields by time-varying electric fields. Maxwell came up with this rather curious name because many of his ideas regarding electric and magnetic fields were completely wrong. For instance, Maxwell believed in the æther, and he thought that electric and magnetic fields were some sort of stresses in this medium. He also thought that the displacement current was associated with displacements of the æther (hence, the name). The reason that these misconceptions did not invalidate his equations is quite simple. Maxwell based his equations on the results of experiments, and he added in his extra term so as to make these equations mathematically self-consistent. Both of these steps are valid irrespective of the existence or non-existence of the æther.
``But, hang on a minute,'' you might say, ``you can't go around adding terms to laws of physics just because you feel like it! The field equations (400)-(403) are derived directly from the results of famous nineteenth century experiments. If there is a new term involving the time derivative of the electric field which needs to be added into these equations, how come there is no corresponding nineteenth century experiment which demonstrates this? We have Faraday's law which shows that changing magnetic fields generate electric fields. Why is there no ``Joe Blogg's'' law that says that changing electric fields generate magnetic fields?'' This is a perfectly reasonable question. The answer is that the new term describes an effect which is far too small to have been observed in nineteenth century experiments. Let us demonstrate this.
First, we shall show that it is comparatively easy to detect the induction of an electric field by a changing magnetic field in a desktop laboratory experiment. The Earth's magnetic field is about 1 gauss (that is, $10^{-4}$ tesla). Magnetic fields generated by electromagnets (which will fit on a laboratory desktop) are typically about one hundred times bigger that this. Let us, therefore, consider a hypothetical experiment in which a 100 gauss magnetic field is switched on suddenly. Suppose that the field ramps up in one tenth of a second. What electromotive force is generated in a 10 centimeter square loop of wire located in this field? Faraday's law is written

$\begin{displaymath}
V = -\frac{\partial}{\partial t} \oint {\bf B}\cdot d{\bf S} \sim \frac{ B A}{t},
\end{displaymath}$ (414)

where

Let us now consider the electric induction of magnetic fields. Suppose that our electric field is generated by a parallel plate capacitor of spacing one centimeter which is charged up to volts. This gives a field of volts per meter. Suppose, further, that the capacitor is discharged in one tenth of a second. The law of electric induction is obtained by integrating Eq. (413), and neglecting the first term on the right-hand side. Thus,

$\begin{displaymath}
\oint {\bf B} \cdot d{\bf l} = \epsilon_0 \mu_0 \frac{\partial}{\partial t}\!
\int {\bf E} \cdot d{\bf S}.
\end{displaymath}$ (415)

Let us consider a loop 10 centimeters square. What is the magnetic field generated around this loop (we could try to measure this with a Hall probe). Very approximately, we find that

$\begin{displaymath}
l B \sim \epsilon_0 \mu_0 \frac{ E l^2}{t},
\end{displaymath}$ (416)

where
Let us now consider the electric induction of magnetic fields. Suppose that our electric field is generated by a parallel plate capacitor of spacing one centimeter which is charged up to volts. This gives a field of volts per meter. Suppose, further, that the capacitor is discharged in one tenth of a second. The law of electric induction is obtained by integrating Eq. (413), and neglecting the first term on the right-hand side. Thus,

$\begin{displaymath}
\oint {\bf B} \cdot d{\bf l} = \epsilon_0 \mu_0 \frac{\partial}{\partial t}\!
\int {\bf E} \cdot d{\bf S}.
\end{displaymath}$ (415)

Let us consider a loop 10 centimeters square. What is the magnetic field generated around this loop (we could try to measure this with a Hall probe). Very approximately, we find that

$\begin{displaymath}
l B \sim \epsilon_0 \mu_0 \frac{ E l^2}{t},
\end{displaymath}$ (416)

where l=0.1 meters is the dimensions of the loop, is the magnetic field-strength,

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